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Sweet Sixteener (Posted on 2005-02-03) Difficulty: 2 of 5
For this problem, only positive whole numbers are to be considered. What is the smallest number that has exactly 16 numbers (including 1 and itself) that divide into it without remainder? Proof?

See The Solution Submitted by Richard    
Rating: 4.0000 (2 votes)

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re(2): Solution -- wrong -- my dumb typo Comment 5 of 5 |
(In reply to re: Solution -- wrong by Old Original Oskar!)

I knew the solution was 120, it was even in my list.  I think I just typed it wrong.

Our solutions and methods were identical in any case.  I figured I would post mine without looking at yours just in case.

  Posted by Jer on 2005-02-03 20:16:44
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