For this problem, only positive whole numbers are to be considered. What is the smallest number that has exactly 16 numbers (including 1 and itself) that divide into it without remainder? Proof?

(In reply to re: Solution -- wrong by Old Original Oskar!)

I knew the solution was 120, it was even in my list.  I think I just typed it wrong.

Our solutions and methods were identical in any case.  I figured I would post mine without looking at yours just in case.

Posted by Jer on 2005-02-03 20:16:44