For this problem, only positive whole numbers are to be considered. What is the smallest number that has exactly 16 numbers (including 1 and itself) that divide into it without remainder? Proof?
(In reply to re: Solution -- wrong
by Old Original Oskar!)
I knew the solution was 120, it was even in my list. I think I just typed it wrong.
Our solutions and methods were identical in any case. I figured I would post mine without looking at yours just in case.
Posted by Jer
on 2005-02-03 20:16:44