 All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars  perplexus dot info  Proving a witch weighs the same as a duck (Posted on 2005-02-21) Suppose the witch weighs W pounds, and the duck weighs D pounds. Also, suppose their average weight is A pounds. (Their combined weight is 2A)

W + D = 2A. (Given)
W = 2A - D. (Subtract D)
W - 2A = -D (Subtract 2A)
W(W - 2A) = W(-D) (Multiply by W)
W(W - 2A) = (2A - D)(-D) (Substitute 2A-D for W using the given equation)
Wý - 2AW = -2AD + Dý (Distribute)
Wý - 2AW + Aý = Dý - 2AD + Aý (Add Aý)
(W-A)(W-A)=(D-A)(D-A). (Factor)
(W-A)ý = (D-A)². (An expression times itself equals the expression squared)
(W-A) = (D-A) (Square root)

In other words, a witch weighs the same as a duck.

Where did I go wrong?

 See The Solution Submitted by Dustin Rating: 3.0000 (4 votes) Comments: ( Back to comment list | You must be logged in to post comments.) re(2): Monty Python logical method | Comment 10 of 12 | (In reply to re: Monty Python logical method by Bruce Brantley)

What do you mean? An African or European swallow?
 Posted by Larry on 2005-02-23 11:37:05 Please log in:

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