It ain't Fibonacci (Posted on 2005-02-22)

	Submitted by Erik O.
Rating: 4.0000 (2 votes)
Solution:	(Hide)
If you write out the sequence in binary with each next number falling below the previous number you'll start to notice a pattern in the arrangement of ones and zeroes. 00000000 = 0 00000000 = 0 00000001 = 1 00000011 = 3 00000010 = 2 00000110 = 6 00000101 = 5 00001101 = 13 00001100 = 12 00001110 = 14 00001011 = 11 00011011 = 27 00011000 = 24 00111000 = 56 00110001 = 49 00110111 = 55 . . . The ones column repeats in 2s, the twos column repeats in 3s, the fours column repeats in 5s, the eights column repeats in 7s... Each larger column repeats in order of prime numbers. Therefore, the next number in the sequence should be 56.

	Subject	Author	Date
	answer	K Sengupta	2008-11-15 06:53:57
	re: Just to wrap it up...	Erik O.	2005-03-01 18:51:55
	re: Partial Solution (numbers in binary)	Dustin	2005-02-28 21:16:53
	Partial Solution	Dustin	2005-02-28 20:30:02
	Just to wrap it up...	yocko	2005-02-28 20:10:24
	re: Solution (if errors in sequence)	Erik O.	2005-02-28 19:03:46
	Solution (if errors in sequence)	Jer	2005-02-28 17:42:44
	Another hint (probably spoiler)	Erik O.	2005-02-28 13:56:35
	re: Hint	Erik O.	2005-02-24 15:30:51
	Hint	Ptolemy	2005-02-23 02:42:29