Find all postive integer solutions to the equation x^yy^x=x+y.
(In reply to
Am I wrong ? by pcbouhid)
You wrote:
So, [x^(y1)  1] = k1.(x1) for some integer value of k1.
And [y^(x1)  1] = k2.(y1) for some integer value of k2.
but k1 and k2 are polynomials. For example if y=3, k1=(x+1).
My hope would be that since as you found an x^2 this somehow yields the two solutions we found and this additional polynomial give no others.

Posted by Jer
on 20050307 17:04:42 