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Sastry's Evil Bisectors (Posted on 2005-03-04) Difficulty: 5 of 5
Prove that if a right triangle has all sides of integral length, then it has at most one angle bisector of integral length.

No Solution Yet Submitted by owl    
Rating: 4.2000 (5 votes)

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Jer's arithmetic needs work... | Comment 3 of 10 |
Jer, simplifying

b/c = 2(b/x)^2 - 1

I get:

x = b[2c/(b+c)]^0.5
  Posted by vertigo on 2005-03-04 19:15:46
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