Prove that if a right triangle has all sides of integral length, then it has at most one angle bisector of integral length.
... it seems the crux is likely to show that, when a^2 + b^2 = c^2 and a, b and c are intergral then (2c) and (b+c) cannot both be perfect squares.
This is just a guess, of course. This question is beyond my skills.
Posted by vertigo
on 2005-03-04 22:21:08