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 Boring, boring... (Posted on 2005-03-06)
You have a 3x3x3 cube. You bore a circular hole, of diameter 1, from the center of the top face to the center of the bottom face. You bore a similar hole from the left face center to the right face center, and another hole from front center to back center. How much material was removed?

 See The Solution Submitted by Federico Kereki Rating: 4.4286 (7 votes)

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 Monte Carlo approximation (numerical spoiler present) | Comment 4 of 13 |

The volume of material removed from all but the central 1x1 cubelet is 6*pi*(1/4)^2, or about 4.712.

The following program chooses points at random in the central cubelet and finds what fraction are within any of the three cylinders:

DEFDBL A-Z
RANDOMIZE TIMER
DO
x = RND(1) - .5#: x2 = x * x
y = RND(1) - .5#: y2 = y * y
z = RND(1) - .5#: z2 = z * z
IF x2 + y2 < .25# OR x2 + z2 < .25# OR y2 + z2 < .25# THEN
hit = hit + 1
END IF
tries = tries + 1
IF tries MOD 1000 = 0 THEN PRINT hit, tries, hit / tries
LOOP

It finds about .942 as the volume of the portion of the central cubelet that is removed. Together with the purely cylindrical portions that comes to 5.654.

 Posted by Charlie on 2005-03-06 17:42:42

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