There is a bag with balls numbered 1 to 9. Two players take turns at randomly taking a ball from the bag. If a player gets three balls that sum fifteen, he wins. Getting fifteen with more or less balls doesn't count.
What are the odds of the first player winning? Of a draw?
"Getting fifteen with more or less balls doesn't count". It means that only counts the three first balls for each player?
If is like that, a possible way is: as the first playing wins in the fifth ball, his possibility of winning is the possibility of forming numbers of five digits in which the digits one, three and five totalized 15. Which is 0.055 (perhaps: my maths are full of dust) .
Posted by armando
on 2005-03-24 19:23:35