There is a bag with balls numbered 1 to 9. Two players take turns at randomly taking a ball from the bag. If a player gets three balls that sum fifteen, he wins. Getting fifteen with more or less balls doesn't count.

What are the odds of the first player winning? Of a draw?

I got the following win probabilities (roughly):

player 1: 53.03%

player 2: 25.31%

draw: 21.65%

Posted by Derek Hyatt on 2007-02-19 11:01:25