All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Power inequality (Posted on 2005-03-15) Difficulty: 3 of 5
Prove that for all positive x, y, and z,

(x+y)^z+(y+z)^x+(z+x)^y > 2.

See The Solution Submitted by e.g.    
Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): am I wrong ? | Comment 4 of 18 |
(In reply to re: am I wrong ? by Richard)

Richard,

I discover that this sum has a POINT OF INFLEXION, near to 2.5, for z = 0,183.......... I don't know what represents this number.

You could see it using Excel.

My mistake is the conclusion that the sum is >=3. But it is indeed greater than 2.


  Posted by pcbouhid on 2005-03-16 13:07:28
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information