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Power inequality (Posted on 2005-03-15) Difficulty: 3 of 5
Prove that for all positive x, y, and z,

(x+y)^z+(y+z)^x+(z+x)^y > 2.

See The Solution Submitted by e.g.    
Rating: 3.0000 (1 votes)

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re(4): am I wrong ? | Comment 6 of 18 |
(In reply to re(3): am I wrong ? by Michael Cottle)

Michael,

With no doubt I'm much older than all of you (and if you don't know yet, I'm brazilian, and excuse for possible mistakes in my english).

Math and logic are my passion since I was a kid. I'm always buying and reading books about them.

One thing I've learned in the study of Math. Math is so beautiful, so consistent, that I'm prepared to bet a million dollars that the minimum of that equation occurs WHEN X = Y = Z. But I didn't, as you, have a proof yet. (we have to discover what is this number : 0,183935...., and run backwards).   

 

 


  Posted by pcbouhid on 2005-03-16 18:43:57
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