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Fibonacci Fractions (Posted on 2005-03-09) Difficulty: 3 of 5
What is the sum of 0.1+ 0.01+ 0.002+ 0.0003+ 0.00005+ 0.000008+ ..., where each term is the n-th Fibonacci number, shifted n places to the right (that is, divided by 10^n)?

  Submitted by e.g.    
Rating: 3.0000 (2 votes)
Solution: (Hide)
10/89. See an explanation here.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionPuzzle Solution: Method IIIK Sengupta2008-05-01 06:32:52
SolutionPuzzle Solution: Method IIK Sengupta2008-05-01 06:31:10
SolutionPuzzle Solution: Method IK Sengupta2008-05-01 06:30:01
answerK Sengupta2007-11-23 03:50:26
re: What I foundDouglas2005-03-31 08:00:52
Clear SolutionEric2005-03-10 06:40:39
Solution with explainationSachin2005-03-09 21:46:30
SolutionExplained solutionFederico Kereki2005-03-09 21:12:57
Very interesting, Charlie...Erik O.2005-03-09 21:09:25
SolutionMmmhhh...Michael Cottle2005-03-09 21:03:06
Solutionre: Extended precision using UBASIC -- base 12 error in added matterCharlie2005-03-09 20:17:56
SolutionExtended precision using UBASICCharlie2005-03-09 20:06:38
re: What I foundBryan2005-03-09 20:01:31
maybeMark2005-03-09 19:56:43
What I foundHugo2005-03-09 19:44:51
Some Thoughtsre: No SubjectDustin2005-03-09 19:14:58
Some ThoughtsNo SubjectDustin2005-03-09 18:52:04
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