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Easy Money (Posted on 2005-03-28) Difficulty: 2 of 5
This week's lottery was won by a syndicate of 10 people, between them they won a total of $2,775,000. They all contributed different amounts into the syndicate and their winnings were calculated against their contributions.

If the amounts were all different but the cash step between each step remained uniform, what amount did the 2nd highest winner get, given that the sum of the lowest three amounts was equal to the sum of the highest two?

See The Solution Submitted by Juggler    
Rating: 2.0000 (2 votes)

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Solution Solution | Comment 1 of 4
The ten values are A, A+B, A+2B, ... A+9B. Their sum is 2,775,000 so 10A+45B=2,775,000. The sum of the first three is the same as the sum of the last two, so 3A+3B=2A+17B, or A=14B. Substituting, 185B=2,775,000, so B=15,000, and then A=210,000. The amounts were 210,000, 225,000, 240,000, etc.
  Posted by Old Original Oskar! on 2005-03-28 15:13:53
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