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Roll the Die Higher (Posted on 2005-04-07) Difficulty: 3 of 5
Two players alternate throwing a six-sided die. The first player who fails to roll a higher number than the preceding roll loses. What is the probability that the first player wins?

What if the die is n-sided?

See The Solution Submitted by Charlie    
Rating: 3.8571 (7 votes)

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Answer | Comment 12 of 13 |

(i) For a six sided die, the required probability that the first player wins is  0.665102 (correct to six places of decimals).

(ii)For a n-sided die, the required probability that the first player wins is  1 - (1 - n^-1)^n.

 

 


  Posted by K Sengupta on 2008-11-26 00:00:23
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