perplexus.info :: Geometry : Just find two!

Just find two! (Posted on 2005-04-27)

Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

See The Solution Submitted by Federico Kereki

Rating: 4.3333 (3 votes)

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May not be possible

| Comment 1 of 25

As the length of BC approaches 0, AQ approaches AC, thus either AP or PQ or both > QB. Do we need some parameters for this puzle?

Posted by Bryan on 2005-04-27 19:29:18

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