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Just find two! (Posted on 2005-04-27)

Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

See The Solution Submitted by Federico Kereki

Rating: 4.3333 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

re: May not be possible

| Comment 3 of 25 |

(In reply to May not be possible by Bryan)

When either of AC or BC is more than twice the other (so that one of then is less then half the other), there is does not exist a valid solution, with P between A and C and Q between B and C.

Posted by Charlie on 2005-04-27 19:49:37

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