Given a triangle ABC, how can you find a point P on AC and a point Q on BC, such that AP=PQ=QB?

N.B. A construction method is sought, and only compass and straightedge are allowed.

(In reply to re(2): May not be possible by Richard)

I understood the same thing -- if the points HAD to be between the vertices of the triangle, the problem could have no solution.

Posted by Old Original Oskar! on 2005-04-27 20:19:07