Home > Logic
| Game Show (Posted on 2005-05-01) |
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On a certain game show, five families were asked to match famous names to faces they were shown, and each correct guess got one point. The families made the following guesses (in order):
The Addams' guessed Otto, Roebling, Steinmetz, Tesla, and Westinghouse.
The Bunkers guessed Tesla, Westinghouse, Otto, Steinmetz, and Roebling.
The Cunninghams guessed Roebling, Tesla, Steinmetz, Westinghouse, and Otto.
The Flintstones guessed Tesla, Roebling, Otto, Steinmetz, and Westinghouse.
The Jetsons guessed Tesla, Westinghouse, Steinmetz, Otto, and Roebling.
No two families got the same number of points. Which family walked home with the grand prize?
Trial and Error question
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 | Comment 5 of 33 | 
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I haven't read the other comments yet, but I was wondering if there was a "good way" to solve these kinds of problems WITHOUT trial and error. Or at least without a 100% trial and error method like the following. Right now, If I were going to try to solve this puzzle my thought process would be "ok, some family had to get ALL of them right, OR some family had to get NONE of them right (or both conditions)." So then I'd go down the list and assume one family got all of them right and see what the others scored until I had a problem (i.e. two families with the same score). If no family could have gotten them all right, then I would go down the list again assuming one family got none right.
But there must be some way of noticing patterns that can help you get to the solution in a not-so-trial-and-errory way.
Thoughts?
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Posted by nikki
on 2005-05-02 12:42:25 |
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