All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Rational sine (Posted on 2005-05-02) Difficulty: 5 of 5
Is there a non-zero rational number q such that sin(q) is rational (radian measure)?

How about a transcendental number with transcendental sine?

No Solution Yet Submitted by lmnop    
Rating: 3.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
some thoghts | Comment 1 of 7

First of all, since the set of algebraic numbers is countable, and since the sine function is injective in [0,pi/2], the image of the trancedentals must be non-countable, and thus must contains at least one number which is not algebraic, hence, there is a trancedental the image of which is also trancedental.

Abount the rational numbers: I don't know tha answer yet, but my guess is there is no such number, the intuition this: define an equialence relation on real numbers such that two numbers are equivalent if they differ by a rational number (a ~ b if and only if a-b=r, r rational). then the set of equivalency classes can be shown to be non-countable. one of these classes is the class of rational numbers. now, for one rational to have a rational sine, the image of the rationals under sine (which is a countable set) must have at least one number is the equivalency class of rationals.

  Posted by ronen on 2005-05-02 21:44:54
Please log in:
Remember me:
Sign up! | Forgot password

Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Copyright © 2002 - 2018 by Animus Pactum Consulting. All rights reserved. Privacy Information