If
E = (F – I + R)
F = (N * O)
H = (F + X)
I = (N + O)
N = 3
0 = 2
R = (N – O)
T = (X + Y)
U = (O + O)
W = (Y + R)
when does
(T+H+I+R+T+E+E+N)-(T+H+R+E+E)
----------------------------- = (T+W+0) ?
(N+I+N+E)-(F+O+U+R)
(All Os ARE the letter Os, not zeros)
(In reply to
perplexed by ben hagen)
I got when 2(x^2)+3xy+(y^2)+21x+13y+40=0, which is just the same thing as what was said before... I like when T=-8 better than never. Because if you multiply each side of (X+Y+8)/0 = X+2Y+3 (what I got) by 0, you get X+Y+8 = 0. Since X+Y = T, substituting and subtracting 8 from both sides gives T=-8, and that works in my opinion.
Many forget that dividing by 0 only means a problem when the numerator isn't 0 (8/0=?) and when you are solving for an unknown (0/0=x, x=?)... When checking equality, it works! (8/0=0 ?but 0/0=0 yes, 0/0=4 yes, 0/0=2948453 yes)
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Posted by Gamer
on 2003-03-12 10:30:47 |
re: perplexed
