sqrt(a) + sqrt(b) = sqrt(x)

How many possible values of x less than or equal to 1000 are there?

I will assume reversals
Let b = int(sqrt(1000-a^2))
then a and b are
 1 31
 2 31
 3 31
 4 31
 5 31
 6 31
 7 30
 8 30
 9 30
10 30
11 29
12 29
13 28
14 28
15 27
16 27
17 26
18 26
19 25
20 24
21 23
22 22
23 21
24 20
25 19
26 18
27 16
28 14
29 12
30 10
31  6
sum up the second column to get 756 solutions

Edited on May 5, 2005, 7:05 pm

Posted by Steve Herman on 2005-05-05 19:02:03