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A flawed proof? (
Posted on 20021220
)
Given:
a=b
. Applying some basic identity transformations, we get:
a=b a^2ab=a^2b^2 a(ab)=(a+b)(ab) a=a+b a=a+a a=2a 1=2
With such a proof, we can show that 1=2, pi=E, 10000000000000=1, etc.... Can you spot the flaw?
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Submitted by
phil
Rating:
2.9167
(12 votes)
Comments: (
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Solution
 Comment 6 of 13 
The step that is not possible is dividing by (ab), because if a=b then ab=0, and one can't divide by zero
Posted by
Jen
on 20021225 10:51:33
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