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 A flawed proof? (Posted on 2002-12-20)
Given: a=b. Applying some basic identity transformations, we get:
```       a=b
a^2-ab=a^2-b^2
a(a-b)=(a+b)(a-b)
a=a+b
a=a+a
a=2a
1=2```
With such a proof, we can show that 1=2, pi=E, 10000000000000=1, etc.... Can you spot the flaw?

 See The Solution Submitted by phil Rating: 2.9167 (12 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Solution | Comment 6 of 13 |
The step that is not possible is dividing by (a-b), because if a=b then a-b=0, and one can't divide by zero
 Posted by Jen on 2002-12-25 10:51:33
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