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A flawed proof? (
Posted on 20021220
)
Given:
a=b
. Applying some basic identity transformations, we get:
a=b a^2ab=a^2b^2 a(ab)=(a+b)(ab) a=a+b a=a+a a=2a 1=2
With such a proof, we can show that 1=2, pi=E, 10000000000000=1, etc.... Can you spot the flaw?
See The Solution
Submitted by
phil
Rating:
2.9167
(12 votes)
Comments: (
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No Subject
 Comment 8 of 13 
you can't divide by 0. (ab) = 0
Posted by
N__A__T__A
on 20030103 07:42:18
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