A piece of wire is to be cut into two pieces (one bent into
the shape of a regular pgon and the other a regular qgon).
If
1) p = 2*q,
2) 2*perimeter(qgon) = 3*perimeter(pgon), and
3) the sum of the two areas is minimized;
then what is the value of q?
From Bractals' comment, I am wondering if he meant condition 2 to be a variable. i.e.:
Let x= the fraction of wire in the pgon (0 <= x <= 1)
So x is a variable instead of being fixed at .4
For different values of q, use calculus to minimize the total area by varying x.
See how x is related to q
For what value of q is x closest to .4
If this is Bractals' intent, then my intuition tells me that as q approaches infinity, (circles), the optimum x approaches .5;
and x will be closest to .4 when q=3
Edited on May 21, 2005, 7:20 pm

Posted by Larry
on 20050521 19:10:30 