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Divisibility by 7 (Posted on 2005-05-22) Difficulty: 2 of 5
(2222^5555 + 5555^2222) is or isn't divisible by 7 ?

Just pencil and paper.

See The Solution Submitted by pcbouhid    
Rating: 2.0000 (3 votes)

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Some Thoughts re: Big numbers are NO PROBLEM for divisibility | Comment 5 of 8 |
(In reply to Big numbers are NO PROBLEM for divisibility by Rupesh Khandelwal)

Rupesh, after what you got in equation (1), you can easily conclude that the given number, that is, 2222^5555 + 5555^2222 is divisible by 7.

Here is the reason why:

5^1111 + 2^1111 ----------------------- Eqn 1

This was your equation (1). Now we know that a^n + b^n is divisible by a + b whenever n is odd, which implies 5^1111 + 2^1111 is divisible by 7, which again in turn implies that 2222^5555 + 5555^2222 is divisible by 7.

That solves our problem. :)
  Posted by Ravi Raja on 2005-05-25 06:05:19

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