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Too many threes and sixes (Posted on 2005-05-25) Difficulty: 2 of 5
The integer A consists only of 666 threes, and the integer B has only 666 sixes.

What digits appear in the product A x B ?

JUST PENCIL AND PAPER !!!

See The Solution Submitted by pcbouhid    
Rating: 4.0000 (5 votes)

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There is a pattern to it | Comment 1 of 10

3*6 = 18

33*66 = 18*11^2 = 2178

333*666 = 18*111^2 = 221778

That's as far as I'll do out by hand, but assuming this pattern continues

333...33*666...66 = 18*111...11 = 22...22177...778

Where '...' stands for 661 more repeated digits.

I'm not ready to try to explain why this is yet.


  Posted by Jer on 2005-05-25 18:09:00
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