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Sugar Cubes (Posted on 2002-12-24) Difficulty: 2 of 5
Three cubes of volume 1, 8, and 64 are glued together.
What is the smallest possible surface area of the resulting configuration?

-Problem taken from UNL Math Day

See The Solution Submitted by cges    
Rating: 3.0909 (11 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: As easy as 1,2,4 (corrections) | Comment 2 of 10 |
(In reply to As easy as 1,2,4 by TomM)

Correction to your math.

First of all, the surfaces areas are 6, 24, 96, for a total of 126.

Secondly, the area would be reduced by 12 (I think you forgot to add 2).

So the minimum area would be 114. Other than these area, I agree completely with your logic (unless there's some obscure way to piece them together).
  Posted by np_rt on 2002-12-24 23:58:32

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