Three cubes of volume 1, 8, and 64 are glued together.

What is the smallest possible surface area of the resulting configuration?

-Problem taken from UNL Math Day

What kind of cubes are they anyways? I mean, I agree with the answer of 114, that's what I got....But I recall another cube problem (remove the center cubefrom a group of cubes) where someone brought up theissue of cubes that were actually wire frames or something.If we had such cubes, the surface area would be SUBSTANTIALLY smaller than 114 wouldn't it?

Whose the nitpicker now?