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Sugar Cubes (Posted on 2002-12-24) Difficulty: 2 of 5
Three cubes of volume 1, 8, and 64 are glued together.
What is the smallest possible surface area of the resulting configuration?

-Problem taken from UNL Math Day

See The Solution Submitted by cges    
Rating: 3.0909 (11 votes)

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Solution Solution | Comment 7 of 10 |
Arrange the cubes so that one face of the one with volume 8 is glued with the one of volume 64 and another face facing to the ground. Then the little one with volume 1 glue it in the corner touching the ground, the one with volume 8 and the one with volume 64.

This arrange would give an area of:
80+16+11+3=110
  Posted by Antonio on 2003-08-22 02:17:20
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