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 Sugar Cubes (Posted on 2002-12-24)
Three cubes of volume 1, 8, and 64 are glued together.
What is the smallest possible surface area of the resulting configuration?

-Problem taken from UNL Math Day

 Submitted by cges Rating: 3.0909 (11 votes) Solution: (Hide) The total surface area of the three cubes (before any gluing occurs) is 96 + 24 + 6 =126. Glue the cubes so that one face of the medium size cube is entirely contained in one face of the largest cube. Then glue on the smallest cube so that two of its faces are entirely contained in the faces of the other two. The resulting surface area is 126 – 2(4) – 2(1) – 2(1) = 114.

 Subject Author Date answer K Sengupta 2008-02-26 23:47:37 Let's be specific.... Jim Alain 2005-01-14 23:24:42 Solution-if you wanna play nitpicking Joe C 2004-02-25 09:30:53 Solution Antonio 2003-08-22 02:17:20 Solution Antonio 2003-08-22 02:09:03 re: Simple Simon met a Pieman who gave Simple Simon a problem called Sugar Cubes. Vinodhan Selvarajalu 2003-05-18 00:46:49 Simple Simon met a Pieman who gave Simple Simon a problem called Sugar Cubes. Tim Axoy 2003-04-13 14:00:48 re(2): As easy as 1,2,4 (corrections) TomM 2002-12-25 02:52:21 re: As easy as 1,2,4 (corrections) np_rt 2002-12-24 23:58:32 As easy as 1,2,4 TomM 2002-12-24 23:48:54

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