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Sugar Cubes (Posted on 2002-12-24) Difficulty: 2 of 5
Three cubes of volume 1, 8, and 64 are glued together.
What is the smallest possible surface area of the resulting configuration?

-Problem taken from UNL Math Day

  Submitted by cges    
Rating: 3.0909 (11 votes)
Solution: (Hide)
The total surface area of the three cubes (before any gluing occurs) is 96 + 24 + 6 =126.
Glue the cubes so that one face of the medium size cube is entirely contained in one face of the largest cube.
Then glue on the smallest cube so that two of its faces are entirely contained in the faces of the other two.
The resulting surface area is 126 2(4) 2(1) 2(1) = 114.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
answerK Sengupta2008-02-26 23:47:37
Let's be specific....Jim Alain2005-01-14 23:24:42
Solution-if you wanna play nitpickingJoe C2004-02-25 09:30:53
SolutionSolutionAntonio2003-08-22 02:17:20
SolutionSolutionAntonio2003-08-22 02:09:03
re: Simple Simon met a Pieman who gave Simple Simon a problem called Sugar Cubes.Vinodhan Selvarajalu2003-05-18 00:46:49
SolutionSimple Simon met a Pieman who gave Simple Simon a problem called Sugar Cubes.Tim Axoy2003-04-13 14:00:48
re(2): As easy as 1,2,4 (corrections)TomM2002-12-25 02:52:21
re: As easy as 1,2,4 (corrections)np_rt2002-12-24 23:58:32
SolutionAs easy as 1,2,4TomM2002-12-24 23:48:54
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