All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
Sweet Sixteen (Posted on 2005-06-12) Difficulty: 3 of 5
16 checkers are placed on an 8 by 8 checkerboard, no two checkers on the same square. Show that some four of the 16 checkers are on the vertices of a parallelogram with positive area.

See The Solution Submitted by McWorter    
Rating: 4.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts re: How about this? | Comment 7 of 11 |
(In reply to How about this? by Liz)

Your placement of checkers exhibits lots of groups four checkers that are vertices of parallelograms.  Can you place the 16 checkers to avoid four vertices of a parallelogram?  Or prove that 16 checkers is just too many checkers to escape forming four vertices of a parallelogram?
  Posted by McWorter on 2005-07-24 22:43:02

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (8)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information