All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 Square pairs (Posted on 2005-06-15)
There are pairs of numbers whose sum and product are perfect squares. For instance, 5 + 20 = 25 and 5 x 20 = 100.

If the smallest number of such a pair is 1090, what is the smallest possible value of the other number? No computers!!

 See The Solution Submitted by pcbouhid Rating: 2.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Puzzle Solution Comment 7 of 7 |
(In reply to answer by K Sengupta)

Let the minimum value of the other number be T.

By the problem, 1090*T is a perfect square. Since 1090 does not admit any perfect square divisor, it follows that: T = 1090*(U^2), for some positive integer U.

Again, (1090 + T) is a perfect square.
-> 1090(1 + U^2) = W^2, for some integer W. Thus 1090 must divide W, so that: W = 1090*M, for some M

Therfore, we must have: 1090(1 + U^2) = (1090*M)^2
-> U^2 = 1090*(M^2 - 1)

Now, we observe that the minimum positive integer M occurs at M = 1, giving:

U^2 = sqrt(1089) = 33

Substituting this in the original expression for T, we obtain:

T = 1090*(33^2) = 1187010

Consequently, the required smallest possible value of the other number is 1187010.

Edited on November 22, 2008, 2:36 am
 Posted by K Sengupta on 2008-11-21 23:49:04

 Search: Search body:
Forums (0)