Without using any arithmetical symbols (+, , *, /, or similar; other math symbols; decimal comma or periods; letters; even parentheses) or, in short, anything but the digits, build a number with the digits 1, 3, 5, 7 and 9, that is equal to a number built with the digits 2, 4, 6 and 8 (each digit used once and only once).
Note: This is not a trick. It was extracted from a book edited by Angela Dunn, a mathematician who gathered problems that appeared in many scientific periodical revues!
(In reply to
re: Different Approach by pcbouhid)
I think Lisa is may also be thinking about how to use calculator
digits, such when the display is inverted, produces a word (or
something in that line of thought)
Trick? Well? The 4x4 square did embody one, I'll forgive her the thought.
But ... there still appears to be a .. dare I say it? ... trick. I think that 'owl' had a good thought.
If we only have exclusive use of the digits, then it seems to me that
either numerals (within a given bases) or numerals raised to a
power, .... and then .. we might combine both thoughts, has
possibilities.
Powers! With the Odd digit set, no matter what I take as my base,
the others become my power index, and so give an odd
numeral. The same process with the even digits yields ...
even.
NO Joy.
Is there a configuration where an odd numeral A, raised to the
power Q within base system X equates to an even numeral which is
similarly structured?

Posted by brianjn
on 20050701 14:25:12 