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 123456 (Posted on 2005-07-04)
What six digit number added to itself five times will give a sum each time having the same 6 digits as the original number?

(It's not 000000.)

 See The Solution Submitted by Erik O. Rating: 3.4000 (5 votes)

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 Trial and Error | Comment 3 of 21 |
(In reply to Wild guess by Penny)

Answer same as Penny's, from

DEFLNG A-Z
FOR d1 = 1 TO 9
used(d1) = 1
t1 = d1 * 100000
FOR d2 = 0 TO 9
IF used(d2) = 0 THEN
used(d2) = 1
t2 = t1 + d2 * 10000
FOR d3 = 0 TO 9
IF used(d3) = 0 THEN
used(d3) = 1
t3 = t2 + d3 * 1000
FOR d4 = 0 TO 9
IF used(d4) = 0 THEN
used(d4) = 1
t4 = t3 + d4 * 100
FOR d5 = 0 TO 9
IF used(d5) = 0 THEN
used(d5) = 1
t5 = t4 + d5 * 10
FOR d6 = 0 TO 9
IF used(d6) = 0 THEN
used(d6) = 1
t6 = t5 + d6

t = t6
FOR i = 1 TO 5
t = t + t6
flag = 1: t\$ = LTRIM\$(STR\$(t))
FOR j = 1 TO LEN(t\$)
d = VAL(MID\$(t\$, j, 1))
IF used(d) = 0 THEN flag = 0: EXIT FOR
NEXT
IF flag = 0 THEN EXIT FOR
NEXT i
IF flag THEN PRINT t6

used(d6) = 0
END IF
NEXT d6
used(d5) = 0
END IF
NEXT d5
used(d4) = 0
END IF
NEXT d4
used(d3) = 0
END IF
NEXT d3
used(d2) = 0
END IF
NEXT d2
used(d1) = 0
NEXT d1

 Posted by Charlie on 2005-07-04 18:47:29

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