All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
123456 (Posted on 2005-07-04) Difficulty: 2 of 5
What six digit number added to itself five times will give a sum each time having the same 6 digits as the original number?

(It's not 000000.)

See The Solution Submitted by Erik O.    
Rating: 3.4000 (5 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Wild guess -= To Hugo | Comment 9 of 21 |
(In reply to re: Wild guess by Hugo)

Hugo, reading better your work, you said :

"If there is a 1 in the six digit number, there also needs to be at least one (odd) digit to get the number when 1 is at the end of the six digit number".

What makes you think that in the 6 numbers, in at least one of them, the 1 will be at the end ?

In fact, there is one of six-digit ending in 1. But you started your reasoning based on this, without proving it !

(In few lines itīs not difficult to show that the number is odd, divisible by 9, and there is a 8 in it, also.)

I think that something is missing yet, though we all know that the number is 142857.

 

  

 


  Posted by pcbouhid on 2005-07-05 22:57:41
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (9)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information