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Thirds and Differences (Posted on 2005-07-21) Difficulty: 2 of 5

Arrange the digits 1-9 so that the first 3 form a number that is 1/3 of the number formed by the last three and the three digits in the middle form a number that is the difference between them.

The numbers are as they appear, not summed.

No Solution Yet Submitted by Erik O.    
Rating: 3.0000 (3 votes)

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re: My solution | Comment 6 of 9 |
(In reply to My solution by Lisa)

I get 5:

<table x:str="" style="border-collapse: collapse; width: 48pt;" border="0" cellpadding="0" cellspacing="0" width="64"> <col style="width: 48pt;" width="64"> <tbody><tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt; width: 48pt;" height="17" width="64">192384576</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">219438657</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">267534801</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">273546819</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">327654981</td> </tr></tbody> </table>

  Posted by Daniel Lurie on 2005-08-03 18:30:42

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