Arrange the digits 1-9 so that the first 3 form a number that is 1/3 of the number formed by the last three and the three digits in the middle form a number that is the difference between them.

The numbers are as they appear, not summed.

(In reply to My solution by Lisa)

I get 5:

<table x:str="" style="border-collapse: collapse; width: 48pt;" border="0" cellpadding="0" cellspacing="0" width="64"> <col style="width: 48pt;" width="64"> <tbody><tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt; width: 48pt;" height="17" width="64">192384576</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">219438657</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">267534801</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">273546819</td> </tr> <tr style="height: 12.75pt;" height="17"> <td class="xl22" style="height: 12.75pt;" height="17">327654981</td> </tr></tbody> </table>

Posted by Daniel Lurie on 2005-08-03 18:30:42