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Word2Num (Posted on 2005-07-15) Difficulty: 3 of 5
WORD2NUM means:
Any method or procedure that converts any word or group of letters into a unique integer.
Given the method and the integer, one can figure out the word. Not all integers correspond to a word.
A specific procedure might work only with a specific alphabet, but with slight modification could be made to work with another alphabet.

To decipher this message, you need to figure out what WORD2NUM procedure I used.

First here is a partial "Rosetta Stone".
ALL = 13737
YOUR = 1618515
ARE = 13946
BELONG = 689654284
TO = 1068
US = 1108
WHAT = 1515413
YOU = 44958
SAY = 36682
MAIN = 1040063
SCREEN = 1714486703
TURN = 1392899
ON = 887

Here is the ciphertext:
831805 21303239 48023009 48023009 1235714990931 17741 16438 48023009 23842631010 48023009 370 1086220895 52925280 17741 13993 891 926381 1008910850 13737 1618515 527198 13946 689654284 1068 1108 38112134

See The Solution Submitted by Larry    
Rating: 4.0000 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re(2): Procedure still eludes... (hint)...and my process | Comment 7 of 9 |
(In reply to re: Procedure still eludes... (hint) by Charlie)

Ahhh, is that why the word "base" is missing from the Rosetta stone?  A clue perhaps to the solution.

Another comment on the Rosetta stone word choices is the appropriateness of numbers of words of certain lengths...one of the reasons I think Larry did such a good job with this problem.

I tried a very simple approach, shown here for two-letter words.

A*(letter value 1) + B*(letter value 2) + C = cipher word

Which means three unknowns for the two-letter word formula.  As luck (or design) would have it, there are 3, two letter words in the Rosetta stone.

This yielded A=36, B = 1, C = 333.

A similar process for three-letter words yields 4 unknowns and, whattaya know, 4 three-letter words.  This yielded A=1296, B=36, C=1, D=11997.

The pattern starts to become clear.  1296=36^2.  11997=333*36+9.  This then led back to 333=9*36+9. 

PS.  If you realized that "base" was missing from the Rosetta stone and found it's value in the message, you could solve for parameters for four-letter words as well.

Edited on July 18, 2005, 2:19 pm
  Posted by Bob Smith on 2005-07-18 13:41:05

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