perplexus.info :: Numbers : Any order will do

Any order will do (Posted on 2005-07-12)

The numbers from 1 to 2n are separated into two lists of n numbers each, A and B; elements are ordered so a₁<a₂<...<a_n and b₁>b₂>...>b_n.

How much is |a₁-b₁|+|a₂-b₂|+...+|a_n-b_n|?

See The Solution Submitted by Federico Kereki

Rating: 3.6667 (3 votes)

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answer

Comment 8 of 8 |

The given expression |a₁-b₁|+|a₂-b₂|+...+|a_n-b_n| sums to n^2.

Posted by K Sengupta on 2010-05-29 04:10:32

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