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Any order will do (Posted on 2005-07-12) Difficulty: 3 of 5
The numbers from 1 to 2n are separated into two lists of n numbers each, A and B; elements are ordered so a1<a2<...<an and b1>b2>...>bn.

How much is |a1-b1|+|a2-b2|+...+|an-bn|?

See The Solution Submitted by Federico Kereki    
Rating: 3.6667 (3 votes)

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answer Comment 8 of 8 |
The given expression |a1-b1|+|a2-b2|+...+|an-bn| sums to n^2.
  Posted by K Sengupta on 2010-05-29 04:10:32
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