Find 4 different positive integers A,B,C,D for which:
A+B = C*D and
A*B = C+D
How many sets of 4 numbers can you find? Prove that only those sets exist.
We know that all the numbers different positive integers, so there is either one 1 or none.
If there were none, then A+B<A*B, C+D<C*D so A+B<C+D<A+B which is a contradiction, so one of the numbers must be a 1. Since all the numbers are communitive (they can be switched around), I will just say A is 1.
This means B+1=C*D and B=C+D. Substituting in for B gives C+D+1=C*D, and if C>2, D>2 then C+D+1<C*D, so C (or D) must be 2. This means 3+D=2D and D=3, so B=5. This means Nosher's set is the only set that meets the conditions in the problem.

Posted by Gamer
on 20050722 14:23:58 