You have 3 unmarked pitchers that hold 6 cups, 10 cups, and 15 cups. The 10 cup pitcher is filled with lemonade, but you have to dilute it so people at the party don't complain that it's too sour. Unfortunately, I have, in the name of logic, broken your only measuring cup.

How can you dilute the lemonade to 20 cups such that all of the lemonade is of equal concentration? You have a sink with unlimited water, but you can't waste any lemonade. Try using as few moves as possible.

if we look at the core problem we have 10 cups of lemonade concentrate that needs 10 cups of water added to it

• so dump the 10 into the 15 (0 water + 10 lemon)
• fill the 10 with water (10 water + 10 lemon)
• at the same rate, pour both the 10 and 15 into the 6 (6 lemonade + 7 water + 7 lemon)
• dump the 10 into the 15 (6 lemonade + 14 lemonade)

 

Posted by tanx on 2005-10-17 20:40:38