When you draw three circles of radius r such that all three are externally tangent, what is the area of the shape in the center in terms of r?
(In reply to
re: solution..... :) by josh_79_97)
Simplify your answer.
The height of an equilateral triangle with base S is (S¡î3)/2, so the area of this particular triangle is 2r(r¡î3)/2 which simplifies to r©÷(¡î3) and since there are 3 slices each 60¨¬ (1/6 of 360), then the area subtracted is (3/6)(¥ðr©÷) or (¥ðr©÷)/2.
The answer is (r©÷(¡î3))-((¥ðr©÷)/2)
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Posted by Bret
on 2005-08-02 20:37:34 |
re(2): solution..... :)
