Arthur, Bert and Charles took three exams. In all exams, the first got X points, the second Y points, and the third Z points, X, Y and Z being positive integers such that X>Y>Z.
Summing the three results, Albert got 20 points; Bert, 10; and Charles, 9. Albert was 2nd in Algebra. Who was 2nd in Geometry?
There is only one possibility
Albert = 2X and 1Y
Bert = 1X and 2Z
Charles = 2Y and 1Z
and X, Y & Z is 8, 4 & 1 respectively
if Albert came 2nd in algebra in other subjects charles came second
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Posted by salil
on 2006-02-20 08:34:25 |
solution
