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Pair Playing Probability (Posted on 2005-08-02) Difficulty: 3 of 5
There are N players in a tennis tournament. Assuming the initial pairings are done randomly, what are the odds that a certain pair will play each other?

See The Solution Submitted by Old Original Oskar!    
Rating: 3.0000 (2 votes)

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Some Thoughts re(3): I undestood right? - no, WRONG. | Comment 8 of 31 |
(In reply to re(2): I undestood right? - no, WRONG. by pcbouhid)

If the odds of A and B playing in the first round were 1/C(N,2) as you say, then the odds of A and C would be the same, and so A and D, A and E, etc.

However, then the odds of A playing ANYBODY would be (N-1) times 1/C(N,2), and that doesn't equal 1!

A can play any of the other N-1 players in the first round, so the odds of him playing anybody in particular are 1/(N-1)

  Posted by Federico Kereki on 2005-08-02 20:09:12

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