The quadratic equation x^2-3x+2=0 has the "correct" number of solutions modulo 5 and 7. However, modulo 6 the equation has four solutions; namely, 1, 2, 4, and 5. For what positive integers n does the equation x^2-3x+2=0 have exactly two incongruent solutions modulo n?
(In reply to
re(6): Proof by Richard)
Ok, I hope that clears up things for everyone.
And you are right; x^2-4x+3=0 is different. Only two solutions mod 6.
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Posted by McWorter
on 2005-09-04 05:39:40 |
re(7): Proof
