The goal is to continue a perspective drawing of a floor tiled with congruent square tiles. Specifically, let XY be a horizontal line representing the horizon of the perspective drawing. Let ABCD be one of the square tiles in the foreground, with A nearest the viewer, B on the line XA, D on the line YA, and C the intersection of lines XD and YB. Show how to construct the tile next to ABCD with side BC in common with tile ABCD.

Very similar to other solutions.

Let Z be the intersection of AC and XY.
Let E be the intersection of ZB and DX.
Let F be the intersection of YE and AX.

Posted by Tristan on 2005-08-28 04:09:03