All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Just Math
2003 - An odyssey with pi and e (Posted on 2005-10-09) Difficulty: 3 of 5
These are the initials decimals of pi and e:

Decimals of pi: 1415926535897932384626433832795...
Decimals of e : 7182818284590452353602874713526...

Without rearranging the order of the digits, add any quantity of parentheses and arithmetic signs +, -, *, / (with same manner in both line) so that to make correct arithmetic expressions equally to 2003, using the least possible number of symbols. You have to use the digits starting from the left one, and the same numbers of digits in each case.

Example for number 11, using the first 5 digits:

- (1 * 4) + 1 + 5 + 9 = 11
- (7 * 1) + 8 + 2 + 8 = 11

These two expression contains 12 symbols (5 digits, 2 parentheses and 5 arithmetic signs).

See The Solution Submitted by pcbouhid    
Rating: 3.1111 (9 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution easy as pi e | Comment 5 of 9 |

...just kidding. it was quite hard. good challenge though!

1 * (41 * 5 9 + 26) + 5 * 358 - 9 = 2003

7 * (18  * 2 - 8 + 18) + 2 * 845 - 9 = 2003

do you know if there's a solution that uses less than 21 symbols?

BTW, thanks for the hint. without it, it was way too hard.

Edited on October 14, 2005, 10:14 am
  Posted by brad on 2005-10-14 10:10:45

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2017 by Animus Pactum Consulting. All rights reserved. Privacy Information