“We – A, B and C – each have some children.

(i) A has at least one girl and twice as many boys as girls.

(ii) B has at least one girl and three times as many boys as girls.

(iii) C has at least one girl and three more boys than girls.

(iv) When I tell you the number of children we have – a number less than 25 – you will know how many children I have, but not how many children each of the others has. Altogether we have……..”

Who is the speaker and how many children does the speaker have?

The speaker is B, who has 4 children.

With a toal of 14 children for all parties, B must have 4. A could have 3 or 6, and C could have 4 or 7.

Posted by Jim McCrank on 2003-01-28 08:35:40