All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars
 perplexus dot info

 The Dice Game (Posted on 2005-11-04)
In a game show, there is a certain game in which there are four hidden digits. There are no numbers greater than six among them, and no zeros.

You roll a die and then guess if the first digit is higher or lower than what you rolled. (If the die you rolled is equal to the first digit, you win no matter what you said.) You then roll and guess for each of the other three digits.

If you use the best strategy each time when saying "higher" or "lower", what is the chance you will get all four right and win? (Keep in mind you have no idea what the 4 digit number is.)

 See The Solution Submitted by Gamer Rating: 3.6667 (3 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
 Solution | Comment 7 of 12 |
If you roll a 1 you guess "higher"
If you roll a 2 you guess "higher"
If you roll a 3 you guess "higher"
If you roll a 4 you guess "lower"
If you roll a 5 you guess "lower"
If you roll a 6 you guess "lower"

If you roll a 1 you have a 6 in 6 shot in the right number
If you roll a 2 you have a 5 in 6 shot in the right number
If you roll a 3 you have a 4 in 6 shot in the right number
If you roll a 4 you have a 4 in 6 shot in the right number
If you roll a 5 you have a 5 in 6 shot in the right number
If you roll a 6 you have a 6 in 6 shot in the right number

You have a 30 in 36 shot in the right number for each number
You have a 120 in 144 shot in the right number for each number

120/144 = .833 which is a 83% chance of guessing the right number and winning.

 Posted by Heather on 2005-11-10 23:41:44

 Search: Search body:
Forums (0)