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The flooble question (Posted on 2003-02-18) Difficulty: 4 of 5
At flooble there are 40 problems in the queue. (this may not be true but lets just pretend it is.) A few crazy hackers somehow manage to promote themselves to scholars. On the first day the first hacker will vote thumbs up on all problems displayed.(The 10 most recent) On the second day the second hacker votes thumbs down on every second problem. On the third day the third hacker votes thumbs up on every third problem. And so on and so on. (When it gets to the eleventh day the eleventh hacker will do what the first hacker did)

How many days will it take for every problem in the queue to be live on the site?

Note: For those who don't know there are only 10 problems that can be voted thumbs up or thumbs down every day and these problems are the 10 least recent. Also a problem with three thumbs up will be posted to the site and taken out of queue. Only one problem can be posted to the site per day. Also if a problem gets 3 thumbs down it is deleted.

Btw: for those who like an extra challenge what if one problem is submitted every 3 days?

Also: A hacker will always vote before a problem becomes live.

See The Solution Submitted by Alan    
Rating: 4.0000 (10 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
re: crazy (for lack of a better subject) | Comment 20 of 51 |
(In reply to crazy (for lack of a better subject) by Cory Taylor)

Thinking about this some more, I see that you're assuming 50 votes have been made over the first 5 days. That's impossible given the skipping over, no matter which puzzle the voter starts voting on. The second voter makes only 5 votes and the third 3. The fourth makes only 3 votes as well, and the fifth makes only two votes. The sixth makes one by my original assumption, but still only two even if he starts with puzzle 1. The same holds for the seventh , eighth and ninth voters, and the tenth votes only once on his day.
  Posted by Charlie on 2003-02-18 07:08:42

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