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 Pick two numbers! (Posted on 2005-11-22)
Yesterday I bought two tickets to a movie, which logically had consecutive numbers. I examined the numbers, which had four digits, and mentioned that the sum of the eight digits was 25.

A friend asked if any digit appeared more than twice out of the eight, and I answered him.

Other friend asked if the sum of the digits of either ticket was equal to 13, which I also answered.

And then, to my surprise, my daughter told me what the two numbers were!

What were they?

 Submitted by e.g. Rating: 3.8889 (9 votes) Solution: (Hide) Suppose I answered that one of the tickets' digits summed 13. The tickets could have been numbered ABCD and ABC(D+1) with D<9 and you couldn't work out the numbers, since all you'd have is that A+B+C+D=12. So I answered "NO" to the second question, and the numbers aren't ABCD and ABC(D+1). If the tickets had been numbered ABC9 and AB(C+1)0, with C<9, then the sum of the digits would have been even, so this case is impossible. Finally, as the numbers cannot be A999 and (A+1)000 --for the sum exceeds 25-- the tickets must have been AB99 and A(B+1)00, so A+B=3, allowing 0399-0400, 1299-1300, 2199-2200, and 3099-3100. In three of these I would have answered "YES" to the question about a number appearing more than twice; since my daughter could work out the numbers, I must have answered "NO" and the tickets were 1299-1300.

 Subject Author Date Answer K Sengupta 2008-11-16 14:11:30 ticket trivia cassie 2006-01-05 08:32:35 No Subject James 2005-11-25 15:53:23 Answer to the Two Ticket Problem Gordon Steel 2005-11-24 16:58:55 *sizzle* FastJazzy 2005-11-23 22:52:43 my answer Scott 2005-11-23 04:11:14 re: I disagree James 2005-11-23 00:32:18 re: I disagree Mindy Rodriguez 2005-11-23 00:31:38 I disagree James 2005-11-23 00:25:25 re: soln Mindy Rodriguez 2005-11-22 22:55:36 my answer Vernon Lewis 2005-11-22 12:46:55 Solution Neil 2005-11-22 12:42:14 Solution Roscoe 2005-11-22 12:18:04 My solution pcbouhid 2005-11-22 11:48:19 soln doubledos 2005-11-22 11:00:52

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